A) \[{{65}^{o}}\]
B) \[{{73}^{o}}\]
C) \[{{62}^{o}}\]
D) \[{{60}^{o}}\]
Correct Answer: C
Solution :
Since, CG||DF and CE is transversal. \[\therefore \] \[\angle GCE=\angle FDE\] (Corresponding angles) \[\Rightarrow \] \[\angle GCE={{28}^{o}}\] Now, \[\angle ACE={{90}^{o}}\](given) \[\Rightarrow \] \[\angle ACG+\angle GCE={{90}^{o}}\] \[\angle ACG+{{28}^{o}}={{90}^{o}}\] \[\therefore \] \[\angle ACG={{90}^{o}}-{{28}^{o}}={{62}^{o}}\] Also, \[BH||CG\]and CA is transversal. \[\therefore \] \[\angle Y=ACG\] (Corresponding angles) \[\Rightarrow \] \[\angle Y={{62}^{o}}\]You need to login to perform this action.
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