A) \[60{}^\circ \]
B) \[70{}^\circ \]
C) \[80{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: D
Solution :
(d):\[\angle SOT=\angle POS+\angle POT=\frac{1}{2}\] \[(\angle POQ+POR):\] (Mind of a mathematician). This result should elicit in mind of students that for all supplementary angles and angle bisectors drawn, the inside \[\angle les\] are complementary. \[=\frac{1}{2}\,(\angle POQW+\angle POR)=\frac{1}{2}\times 180{}^\circ =90{}^\circ \]You need to login to perform this action.
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