A) \[50{}^\circ \]
B) \[180{}^\circ \]
C) \[130{}^\circ \]
D) \[90{}^\circ \]
Correct Answer: A
Solution :
(a): In \[||\] gm PQRS; \[PQ||SR\] and \[PS||QR\] \[\angle PSR=180{}^\circ -\angle PSE=180{}^\circ -130{}^\circ =50{}^\circ \] By property of transversal, \[\angle QRS=180{}^\circ -\angle PSR=130{}^\circ ;\]Again \[\angle PQR=180{}^\circ -\angle QRS=50{}^\circ \]You need to login to perform this action.
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