A) 6
B) \[\frac{1}{6}\]
C) \[\frac{6}{5}\]
D) \[\frac{5}{6}\]
Correct Answer: D
Solution :
(d): Let \[lo{{g}_{16}}^{64}=n\] Then \[{{16}^{n}}=64\] \[\Rightarrow {{4}^{2n}}=64={{4}^{3}}\] \[2n=3\] \[n=\frac{3}{2}\] Similarly \[\therefore lo{{g}_{64}}16=\frac{2}{3}~\] \[\therefore lo{{g}_{16}}64-lo{{g}_{64}}16=(n-~m)=\left( \frac{3}{2}-\frac{2}{3} \right)=\frac{5}{6}\]You need to login to perform this action.
You will be redirected in
3 sec