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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Lowering of vapour pressure

  • question_answer
    An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is                 [KCET 2002]

    A)             0.02       

    B)                 1

    C)                 20          

    D)                 180

    Correct Answer: A

    Solution :

                \[\frac{{{P}^{0}}-Ps}{{{P}^{0}}}=\frac{18\times 18}{180\times 90}=0.02\].


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