JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Lowering of vapour pressure

  • question_answer
    The vapour pressure of two liquids P and Q are 80 and 600 torr, respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mole of Q would be [CBSE PMT 2005]

    A)                 140 torr 

    B)                 20 torr

    C)                 68 torr   

    D)                 72 torr

    Correct Answer: D

    Solution :

               \[{{P}_{T}}=P_{P}^{0}{{X}_{P}}+P_{Q}^{0}{{X}_{Q}}\];\[{{P}_{T}}=80\times \frac{3}{5}+60\times \frac{2}{5}\]                         \[{{P}_{T}}=48+24=72\ torr\].


You need to login to perform this action.
You will be redirected in 3 sec spinner