A) 50
B) 180
C) 100
D) 25
E) 51
Correct Answer: C
Solution :
Lowering in weight of solution \[\propto \] solution pressure Lowering in weight of solvent \[\propto \] \[{{P}^{0}}-{{P}_{s}}\] (\[\because \] \[{{p}^{0}}=\]vapour pressure of pure solvent) \[\frac{{{p}^{0}}-{{p}_{s}}}{{{p}_{s}}}=\frac{\text{Lowering in weight of solvent}}{\text{Lowering in weight of solution}}\] \[\frac{{{p}^{0}}-{{p}_{s}}}{{{p}_{s}}}=\frac{w\times M}{m\times W}\] \[\frac{0.05}{2.5}=\frac{10\times 18}{90\times m}\]\[\Rightarrow \]\[m=\frac{2\times 2.5}{0.05}=\frac{2\times 250}{5}=100\]
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