A) \[-MB\]
B) \[+MB\]
C) 0
D) \[+2MB\]
Correct Answer: D
Solution :
Work done \[MB(\cos {{\theta }_{1}}-\cos {{\theta }_{2}})\] \[{{\theta }_{1}}={{0}^{o}}\]and \[{{\theta }_{2}}={{180}^{o}}\] \[\Rightarrow W=MB\left( \cos 0-\cos 180 \right)=2MB\]
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