A) \[\frac{{{\mu }_{0}}}{4\pi }\times \frac{M}{{{d}^{3}}}\]
B) \[\frac{{{\mu }_{0}}}{4\pi }\times \frac{M}{{{d}^{2}}}\]
C) \[\frac{{{\mu }_{0}}}{2\pi }\times \frac{M}{{{d}^{3}}}\]
D) \[\frac{{{\mu }_{0}}}{2\pi }\times \frac{M}{{{d}^{2}}}\]
Correct Answer: C
Solution :
\[{{B}_{a}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{d}^{3}}}=\frac{{{\mu }_{0}}}{2\pi }\frac{M}{{{d}^{3}}}\]
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