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JEE Main & Advanced Physics Magnetism Question Bank Magnet and its Properties

  • question_answer
    A small bar magnet of moment M is placed in a uniform field H. If magnet makes an angle of 30° with field, the torque acting on the magnet is                       [CPMT 1989]

    A)            MH

    B)            \[\frac{MH}{2}\]

    C)            \[\frac{MH}{3}\]                 

    D)            \[\frac{MH}{4}\]

    Correct Answer: B

    Solution :

               \[\tau =MH\sin \theta =MH\sin {{30}^{o}}=\frac{MH}{2}\]


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