JEE Main & Advanced Physics Magnetism Question Bank Magnet and its Properties

  • question_answer
    The dipole moment of a short bar magnet is 1.25 A-m2. The magnetic field on its axis at a distance of 0.5metre from the centre of the magnet is

    A)            \[1.0\times {{10}^{-4}}Newton/amp-meter\]

    B)            \[4\times {{10}^{-2}}Newton/amp-metre\]

    C)            \[2\times {{10}^{-6}}Newton/amp-metre\]

    D)            \[6.64\times {{10}^{-8}}Newton/amp-metre\]

    Correct Answer: C

    Solution :

               \[B=\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{d}^{3}}}={{10}^{-7}}\times \frac{2\times 1.25}{{{\left( 0.5 \right)}^{3}}}=2\times {{10}^{-6}}N/A-m\]


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