A) \[4\pi iM\]
B) \[\sqrt{\frac{4\pi M}{i}}\]
C) \[\sqrt{\frac{4\pi i}{M}}\]
D) \[\frac{M\pi }{4i}\]
Correct Answer: B
Solution :
Magnetic moment of circular loop carrying current \[M=IA=I\left( \pi {{R}^{2}} \right)=I\pi {{\left( \frac{L}{2\pi } \right)}^{2}}=\frac{I{{L}^{2}}}{4\pi }\Rightarrow L=\sqrt{\frac{4\pi M}{I}}\]
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