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JEE Main & Advanced Physics Magnetism Question Bank Magnet and its Properties

  • question_answer
    Weber/m2  is equal to                             [CPMT 1985; AFMC 1997]

    A)            Volt                                          

    B)            Henry

    C)            Tesla

    D)            All of these

    Correct Answer: C

    Solution :

               Magnetic flux \[\varphi =BA\Rightarrow B=\frac{\varphi }{A}=\frac{Weber}{{{m}^{2}}}=Tesla\]


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