A) 30o
B) 45o
C) 60o
D) 90o
Correct Answer: C
Solution :
\[\tau =MB\sin \theta \Rightarrow \tau \propto \sin \theta \] \[\Rightarrow \frac{{{\tau }_{1}}}{{{\tau }_{2}}}=\frac{\sin {{\theta }_{1}}}{\sin {{\theta }_{2}}}\Rightarrow \frac{\tau }{\tau /2}=\frac{\sin 90}{\sin {{\theta }_{2}}}\] \[\Rightarrow \sin {{\theta }_{2}}=\frac{1}{2}\Rightarrow {{\theta }_{2}}={{30}^{o}}\] Þ angle of rotation \[=0{\AA}-30=60{}^\circ \]
You need to login to perform this action.
You will be redirected in
3 sec
