A) 2 ´ 10?2 A-m
B) 5 ´ 10?2 A-m
C) 2 A-m
D) 5 A-m
Correct Answer: A
Solution :
\[\tau =MB\sin \theta \Rightarrow \tau =(mL)B\sin \theta \] \[\Rightarrow 25\times {{10}^{-6}}=(m\times 5\times {{10}^{-2}})\times 5\times {{10}^{-2}}\times \sin 30\] \[\Rightarrow m=2\times {{10}^{-2}}A-m\].
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