A) Perpendicular to the field of the earth
B) Parallel to the vertical component of the earth's field
C) At an angle of 33o with respect to the N-S direction
D) Along the North-South (N-S) direction
Correct Answer: A
Solution :
Torque on a bar magnet in earths magnetic field (BH) is \[\tau =M{{B}_{H}}\sin \theta .\] t will be maximum if sin q = maximum i.e. q = 90o. Hence axis of the magnet is perpendicular to the field of earth.
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