A) 8
B) \[1/2\,\,\sqrt{2}\]
C) 3
D) 4
Correct Answer: A
Solution :
Both points A and B lying on the axis of the magnet and on axial position \[B\propto \frac{1}{{{d}^{3}}}\] Þ \[\frac{{{B}_{A}}}{{{B}_{B}}}={{\left( \frac{{{d}_{B}}}{{{d}_{A}}} \right)}^{3}}={{\left( \frac{48}{24} \right)}^{3}}=\frac{8}{1}\]
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