JEE Main & Advanced Physics Magnetism Question Bank Magnet and its Properties

  • question_answer
    A magnet of length 0.1 m and pole strength \[{{10}^{-4}}A.m.\] is kept in a magnetic field of \[30\,Wb/{{m}^{2}}\] at an angle 30°. The couple acting on it is ??? \[\times {{10}^{-4}}Nm.\]    [MP PET 2005]        

    A)            7.5 

    B)            3.0 

    C)            1.5 

    D)            6.0

    Correct Answer: C

    Solution :

                       \[\tau =MB\sin \theta =m\times (2l)\times B\sin \theta \]               \[={{10}^{-4}}\times 0.1\times 30\sin 30{}^\circ \]\[=1.5\times {{10}^{-4}}Nm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner