A) \[0.5\,A\times {{m}^{2}}\]
B) \[5\,A\times {{m}^{2}}\]
C) \[0.250\,A\times {{m}^{2}}\]
D) \[5\times {{10}^{2}}A\times {{m}^{2}}\]
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\] \[I=40gm-c{{m}^{2}}=400\times {{10}^{-8}}kg-{{m}^{2}}\] \[\therefore \ 3=2\pi \sqrt{\frac{400\times {{10}^{-8}}}{36\times {{10}^{-6}}\times M}}\] \[\Rightarrow \frac{1}{M}=\frac{9}{4{{\pi }^{2}}}\times \frac{36}{4}\Rightarrow M=0.5\ A\times {{m}^{2}}\]
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