A) \[2T\]
B) \[T/2\]
C) \[2/T\]
D) \[T\]
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{({{B}_{H}})}_{2}}}{{{({{B}_{H}})}_{1}}}}\] \[\Rightarrow {{T}_{2}}=T\sqrt{\frac{{{(BH)}_{1}}}{{{(BH)}_{2}}}}=\frac{T}{2}\ \ \ \left( \because {{({{B}_{H}})}_{2}}=4{{({{B}_{H}})}_{1}} \right)\]
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