A) \[{{M}_{A}}=2{{M}_{B}}\]
B) \[{{M}_{A}}=8{{M}_{B}}\]
C) \[{{M}_{A}}=4{{M}_{B}}\]
D) \[{{M}_{B}}=8{{M}_{A}}\]
Correct Answer: C
Solution :
\[\nu =\frac{1}{2\pi }\sqrt{\frac{M{{B}_{H}}}{I}}\Rightarrow \nu \propto \sqrt{M}\] \[\Rightarrow \frac{{{\nu }_{A}}}{{{\nu }_{B}}}=\sqrt{\frac{{{M}_{A}}}{{{M}_{B}}}}\Rightarrow \frac{2}{1}=\sqrt{\frac{{{M}_{A}}}{{{M}_{B}}}}\Rightarrow {{M}_{A}}=4{{M}_{B}}\]
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