JEE Main & Advanced
Physics
Magnetism
Question Bank
Magnetic Equipments
question_answer
The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor K will be [NCERT 1983; MP PMT 2002]
A) K
B) 2K
C) 4K
D) K/4
Correct Answer:
A
Solution :
\[K=\frac{2R{{B}_{H}}}{{{\mu }_{0}}N}\] (R = radius, N= number of turns)