A) Q is of non-magnetic material
B) Q is a bar magnet identical to P, and its north pole placed on top of P's north pole
C) Q is of unmagnetized ferromagnetic material
D) Nothing can be said about Q's properties
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\]. If Q is an identical bar magnet then time period of system will be \[{T}'=2\pi \sqrt{\frac{2I}{(2M){{B}_{H}}}}=T\]You need to login to perform this action.
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