A) 45o
B) 48.2o
C) 50.7o
D) 52.7o
Correct Answer: B
Solution :
For tangent galvanometer \[I=\frac{2rB}{{{\mu }_{0}}n}\tan \theta \] \[\therefore \ \tan \theta =\frac{I{{\mu }_{0}}n}{2rB}=\frac{0.1\times 4\pi \times {{10}^{-7}}\times 50}{0.04\times 7\times {{10}^{-5}}\times 2}=1.12\] or \[\theta ={{\tan }^{-1}}\left( 1.12 \right)={{48.2}^{o}}\]You need to login to perform this action.
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