JEE Main & Advanced Physics Magnetism Question Bank Magnetic Equipments

  • question_answer The time period of oscillation of a freely suspended bar magnet with usual notations is given by [CPMT 1973, 76, 87; MP PET 1994, 96]

    A)            \[T=2\pi \sqrt{\frac{I}{M{{B}_{H}}}}\]                           

    B)            \[T=2\pi \sqrt{\frac{M{{B}_{H}}}{I}}\]

    C)            \[T=\sqrt{\frac{I}{M{{B}_{H}}}}\]                                    

    D)            \[T=2\pi \sqrt{\frac{{{B}_{H}}}{MI}}\]

    Correct Answer: A

    Solution :


adversite


You need to login to perform this action.
You will be redirected in 3 sec spinner

Free
Videos