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JEE Main & Advanced Physics Magnetism Question Bank Magnetic Equipments

  • question_answer
    A tangent galvanometer has a coil with 50 turns and radius equal to 4 cm. A current of 0.1 A is passing through it. The plane of the coil is set parallel to the earth's magnetic meridian. If the value of the earth's horizontal component of the magnetic field is \[7\times {{10}^{-5}}\]tesla and\[{{\mu }_{0}}=4\pi \times {{10}^{-7}}weber/amp\times m\], then the deflection in the galvanometer needle will be                            [MP PMT 1993]

    A)            45o

    B)            48.2o

    C)            50.7o                                        

    D)            52.7o

    Correct Answer: B

    Solution :

               For tangent galvanometer \[I=\frac{2rB}{{{\mu }_{0}}n}\tan \theta \] \[\therefore \ \tan \theta =\frac{I{{\mu }_{0}}n}{2rB}=\frac{0.1\times 4\pi \times {{10}^{-7}}\times 50}{0.04\times 7\times {{10}^{-5}}\times 2}=1.12\] or \[\theta ={{\tan }^{-1}}\left( 1.12 \right)={{48.2}^{o}}\]


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