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JEE Main & Advanced Physics Magnetism Question Bank Magnetic Equipments

  • question_answer
    The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor K will be                                       [NCERT 1983; MP PMT 2002]

    A)            K    

    B)            2K

    C)            4K  

    D)            K/4

    Correct Answer: A

    Solution :

               \[K=\frac{2R{{B}_{H}}}{{{\mu }_{0}}N}\]    (R = radius,  N= number of turns)


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