A) Similar poles of both magnets are on same sides
B) Opposite poles of both magnets are on same sides
C) Both magnets are perpendicular to each other
D) Nothing can be said
Correct Answer: B
Solution :
In sum position : \[{{T}_{S}}=2\pi \sqrt{\frac{{{I}_{s}}}{({{M}_{1}}+{{M}_{2}}){{B}_{H}}}}\] In difference position : \[{{T}_{d}}=2\pi \sqrt{\frac{{{I}_{d}}}{({{M}_{1}}-{{M}_{2}}){{B}_{H}}}}\] It is clear that \[{{T}_{d}}>{{T}_{s}}\]
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