A) 0.25 ´ 10?6 T
B) 0.36 ´ 10?6 T
C) 0.66 ´ 10?8 T
D) 1.2 ´ 10?6 T
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{I}{M\times {{B}_{H}}}}\Rightarrow T\propto \frac{1}{\sqrt{{{B}_{H}}}}\] \[\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{({{B}_{H}})}_{2}}}{{{({{B}_{H}})}_{1}}}}\Rightarrow \frac{60/40}{2.5}=\sqrt{\frac{{{({{B}_{H}})}_{2}}}{0.1\times {{10}^{-5}}}}\] \[\Rightarrow {{({{B}_{H}})}_{2}}=0.36\times {{10}^{-6}}T\]
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