JEE Main & Advanced Physics Magnetism Question Bank Magnetic Equipments

  • question_answer
    In a tangent galvanometer a current of 0.1 A produces a deflection of 30o. The current required to produce a deflection of 60o is                                                      [MP PET 2003]

    A)            0.2 A                                        

    B)            0.3 A

    C)            0.4 A                                        

    D)            0.5 A

    Correct Answer: B

    Solution :

               \[i\propto \tan \varphi \Rightarrow \frac{{{i}_{1}}}{{{i}_{2}}}=\frac{\tan {{\varphi }_{1}}}{\tan {{\varphi }_{2}}}\] \[\Rightarrow \frac{0.1}{{{i}_{2}}}=\frac{\tan 30{}^\circ }{\tan 60{}^\circ }=\frac{1}{3}\Rightarrow {{i}_{2}}=0.3A\]


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