A) \[\frac{4\sqrt{3}}{7}\]
B) \[\frac{4}{9\sqrt{3}}\]
C) \[\frac{9}{4\sqrt{3}}\]
D) \[\frac{9}{\sqrt{3}}\]
Correct Answer: C
Solution :
\[T\propto \frac{1}{\sqrt{{{B}_{H}}}}=\frac{1}{\sqrt{B\cos \varphi }}\]\[\Rightarrow \frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{B}_{2}}\cos {{\varphi }_{2}}}{{{B}_{2}}\cos {{\varphi }_{1}}}}\] \[\Rightarrow \frac{{{B}_{1}}}{{{B}_{2}}}=\frac{T_{2}^{2}}{T_{1}^{2}}\times \frac{\cos {{\varphi }_{2}}}{\cos {{\varphi }_{1}}}={{\left( \frac{3}{2} \right)}^{2}}\times \frac{\cos 60}{\cos 30}\]\[\Rightarrow \frac{{{B}_{1}}}{{{B}_{2}}}=\frac{9}{4\sqrt{3}}\]
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