A) \[4\times {{10}^{25}}\]
B) \[3\times {{10}^{25}}\]
C) \[2\times {{10}^{25}}\]
D) \[1\times {{10}^{25}}\]
Correct Answer: A
Solution :
\[M=\frac{\rho \times {{a}^{3}}\times {{N}_{0}}\times {{10}^{-30}}}{z}\] \[=\frac{10\times {{(100)}^{3}}\times (6.02\times {{10}^{23}})\times {{10}^{-30}}}{4}=15.05\] No. of atoms in 100 g \[=\frac{6.02\times {{10}^{23}}}{15.05}\times 100\]\[=4\times {{10}^{25}}\].
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