A) 454
B) 804
C) 852
D) 908
Correct Answer: D
Solution :
For bcc,\[d=\frac{\sqrt{3}}{2}a\]or \[a=\frac{2d}{\sqrt{3}}=\frac{2\times 4.52}{1.732}=5.219\text{{ }\!\!\mathrm{\AA}\!\!\text{ }}=522\,pm\] \[\rho =\frac{Z\times M}{{{a}^{3}}\times {{N}_{0}}\times {{10}^{-30}}}\]\[=\frac{2\times 39}{{{(522)}^{3}}\times (6.023\times {{10}^{23}})\times {{10}^{-30}}}\] \[=0.91\,g/c{{m}^{3}}=910\,kg\,{{m}^{-3}}\]
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