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JEE Main & Advanced Chemistry The Solid State / ठोस प्रावस्था Question Bank Mathematical analysis of cubic system and Bragg's equation

  • question_answer
    The edge of unit cell of FCC \[Xe\] crystal is \[620\,pm\]. The radius of \[Xe\] atom is      [MP PET 2004]

    A)                 219.25 Pm          

    B)                 235.16 Pm

    C)                 189.37 Pm          

    D)                 209.87 Pm

    Correct Answer: A

    Solution :

                    \[r=\frac{a}{2\sqrt{2}}\];   \[r=\frac{620}{2\sqrt{2}}=219.25\,Pm\]


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