A) \[4+12=16\]
B) \[\text{a }\square \text{ c }\!\!\theta\!\!\text{ b}\]
C) \[b\times \text{a}\square c\]
D) \[b\times \text{a}\square c\]
Correct Answer: D
Solution :
\[=\frac{4}{3}-4\times 3+4\] \[=\frac{4}{3}-12+4=-\frac{20}{3}\] \[=18\times 14+6-16\div 4\] \[=18\times 14+6-4=254\] \[-\] \[\div \] \[\frac{5}{9}\] \[=15\div 3+24-12\times 2\] \[=5+24-24=5\]You need to login to perform this action.
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