A) + and \[-\], 2 and 3
B) + and \[-\], 2 and 5
C) + and \[-\], 3 and 5
D) None of these
Correct Answer: A
Solution :
By making the interchanges given in (a), we get the equation as \[\text{3 }\!\!\times\!\!\text{ 2 4 O 6 + 3 2}\] or \[\text{3 + 2 4 O 6 3 }\times \text{ 2}\] which is true. By making the interchanges given in (b), we get the equation as \[\text{3 2 4 - 6 }\times \text{ 3 }\times \text{ 2}\]or \[\text{3 }\times \text{ 2 }\times \text{ 4 = 6 + 3 2}\], which is false. By making the interchanges given in (c), we get the equation as \[3+2-4>6x3+2\] or \[3\div 2-4>6x3+2\] which is not true. So, the answer is (a).
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