A) 12
B) 18
C) 25
D) 16
Correct Answer: D
Solution :
The rule is: \[a+b={{a}^{2}}+b;\,\]\[a-b={{a}^{2}}-b;\] \[a\times b={{a}^{2}}\times b\] \[\therefore \] \[8\div 4={{8}^{2}}\div 4=64\div 4=16\]You need to login to perform this action.
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