A) \[({{L}_{1}}''{{L}_{2}})*({{V}_{1}}''{{V}_{2}})\]
B) \[({{L}_{1}}''{{L}_{2}})\,({{V}_{1}}''{{V}_{2}})\]
C) \[[({{L}_{1}}''{{L}_{2}})\,({{V}_{1}}''{{V}_{2}})]*60\]
D) \[({{L}_{1}}'{{L}_{2}})\,({{V}_{1}}'{{V}_{2}})\]
Correct Answer: B
Solution :
Clearly, time taken \[=\frac{\text{sum of lengths of two trains}}{\text{total speed of two trains}}\] \[=\frac{{{L}_{1}}+{{L}_{2}}}{{{V}_{1}}+{{V}_{2}}}=({{L}_{1}}''{{L}_{2}})\,({{V}_{1}}''{{V}_{2}})\]You need to login to perform this action.
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