A) \[40\,\,K\]
B) \[{{100}^{o}}F\]
C) \[-{{40}^{o}}C\]
D) \[-{{100}^{o}}C\]
Correct Answer: C
Solution :
\[C=F\] \[\frac{C}{100}=\frac{F-32}{180}\] \[180\,\,C=100\,\,C-3200\] \[80\,\,C=-3200,\,\,C=-{{40}^{o}}C\]or\[-{{40}^{o}}F\]
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