JEE Main & Advanced Physics Photo Electric Effect, X- Rays & Matter Waves Question Bank Matter Waves

  • question_answer
    What is the de-Broglie wavelength of the \[\alpha -\]particle accelerated through a potential difference V           [RPMT 1996]

    A)            \[\frac{0.287}{\sqrt{V}}\]Å    

    B)            \[\frac{12.27}{\sqrt{V}}\]Å

    C)            \[\frac{0.101}{\sqrt{V}}\]Å    

    D)            \[\frac{0.202}{\sqrt{V}}\]Å

    Correct Answer: C

    Solution :

                       \[\lambda =\frac{h}{\sqrt{2mE}}=\frac{h}{\sqrt{2{{m}_{\alpha }}{{Q}_{\alpha }}V}}\] On putting \[{{Q}_{\alpha }}=2\times 1.6\times {{10}^{-19}}C\] \[{{m}_{\alpha }}=4{{m}_{p}}=4\times 1.67\times {{10}^{-27}}kg\]Þ \[\lambda =\frac{0.101}{\sqrt{V}}{\AA}\]


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