A) 5.47 Å
B) 10.9 Å
C) 2.7 Å
D) None of these
Correct Answer: A
Solution :
\[\lambda =\frac{h}{\sqrt{2mE}}=\frac{6.6\times {{10}^{-34}}}{\sqrt{2\times 9.1\times {{10}^{-31}}\times 5\times 1.6\times {{10}^{-19}}}}\] \[=5.469\times {{10}^{-10}}m=5.47{\AA}\]
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