A) 1
B) 2
C) 3
D) 0
Correct Answer: D
Solution :
\[f(x)=\int_{0}^{x}{t{{e}^{-{{t}^{2}}}}}dt\Rightarrow f'(x)=x{{e}^{-{{x}^{2}}}}=0\Rightarrow x=0\] \[{f}''(x)={{e}^{-{{x}^{2}}}}(1-2{{x}^{2}});\ \ \ {f}''\,(0)=1>0\] \[\therefore \] Minimum value \[f(0)=0\].You need to login to perform this action.
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