A) \[\pi \]
B) \[\pi /3\]
C) \[\pi /4\]
D) \[\pi /2\]
Correct Answer: D
Solution :
Let \[PQ=a\] and \[PR=b\], then \[\Delta =\frac{1}{2}ab\sin \theta \] \[\because \] \[-1\le \sin \theta \le 1\] Since, area is maximum when \[\sin \theta =1\] Þ \[\theta =\frac{\pi }{2}\].You need to login to perform this action.
You will be redirected in
3 sec