A) 0
B) 2
C) 4
D) 6
Correct Answer: D
Solution :
\[f(x)=|x|+\left| x+\frac{1}{2} \right|+|x-3|+\left| x-\frac{5}{2} \right|\] \[={{e}^{x}}\left[ \frac{1+(x-2)\log x}{{{x}^{3}}} \right]\] for \[x\le -\frac{1}{2}\] \[=-2x+6\], for \[-\frac{1}{2}\le x\le 0\] \[\frac{dy}{dx}=0\Rightarrow x=-1\] for \[0\le x\le \frac{5}{2}\] \[=2x+1,\]for \[\frac{5}{2}\le x\le 3\] \[=4x-5,\] for \[x\ge 3\] From the graph, minimum value of the function is 6.You need to login to perform this action.
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