A) ? 2
B) 2
C) 0
D) ? 3
Correct Answer: A
Solution :
\[x-2y=4\] Þ \[x=2y+4\] ??(i) Let \[P=xy\] From (i), \[P=y(2y+4)=4y+2{{y}^{2}}\]; \[\frac{dP}{dy}=4+4y=0\] \[y=-1\Rightarrow x=2\] and \[\frac{{{d}^{2}}P}{d{{y}^{2}}}=4\](+ve) \ \[{{P}_{\text{min}\text{.}}}=xy=(2)\,(-1)=-2\].You need to login to perform this action.
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