A) No maxima and minima
B) One maximum and one minimum
C) Two maxima
D) Two minima
Correct Answer: B
Solution :
\[f(x)=2{{x}^{3}}-3{{x}^{2}}-12x+4\] \[{f}'(x)=6{{x}^{2}}-6x-12\] Now \[{f}'(x)=0\] Þ \[{{x}^{2}}-x-2=0\] Þ \[x=2,\,-1\] Now \[{f}''(x)=12x-6\] Þ \[{f}''(2)=+ve\], \[{f}''(-1)=-ve\] \Given function has one maximum and one minimum.You need to login to perform this action.
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