A) \[\pi \]
B) \[\pi /2\]
C) \[-\pi /2\]
D) \[-\pi /6\]
Correct Answer: A
Solution :
\[y=a\,(1-\cos x)\]Þ\[{y}'=a\sin x\] Þ \[{y}'=0\Rightarrow \sin x=0\] Þ \[x=0,\,\pi \] Now \[{y}''=a\cos x\] Þ \[{y}''(0)=a\] and \[{y}''(\pi )=-a\] Hence y is maximum when \[x=\pi \].You need to login to perform this action.
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