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12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank MCQ - Alternating Currents

  • question_answer
    The output of a step down transformer is measured to be 24 V when connected to a 12W light bulb. The value of the peak current is:                                                                  (NCERT EXEMPLAR)

    A) \[\frac{1}{\sqrt{2}}A\]               

    B) \[\sqrt{2}\,A\]

    C) \[2\,A\]                         

    D) \[2\,\sqrt{2}\,A\]

    Correct Answer: A

    Solution :

    (a) \[\frac{1}{\sqrt{2}}A\] Here,    \[{{V}_{S}}=24\,\,V,{{P}_{S}}=12\,W\]             \[{{l}_{S}}=\frac{{{P}_{S}}}{{{V}_{S}}}=\frac{12}{24}=0.5\,A:\]             \[{{l}_{m}}=\sqrt{2}{{l}_{s}}=\sqrt{2}\times 0.5=\frac{1}{\sqrt{2}}A\]


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