A) 0.27 mA
B) 2.7 A
C) 0.27 A
D) 10 A
Correct Answer: C
Solution :
(c) 0.27 A Here, \[{{P}_{S}}=60\text{ }W,{{l}_{S}}=0.54\text{ }A,\text{ }{{V}_{P}}=220\text{ }V\] \[{{V}_{S}}=\frac{{{P}_{S}}}{{{l}_{S}}}=\frac{60}{0.54}=111\,V\] As \[\frac{{{V}_{S}}}{{{V}_{P}}}=\frac{{{l}_{P}}}{{{l}_{S}}},\] for an ideal transformer \[\therefore {{l}_{P}}=\frac{{{V}_{S}}}{{{V}_{P}}}\times {{l}_{S}}=\frac{111}{220}\times 0.54=0.27\,A\]
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