12th Class Physics Alternating Current / प्रत्यावर्ती धारा Question Bank MCQ - Alternating Currents

  • question_answer
    The rms value of potential difference V as shown in the figure is:

    A) \[\frac{{{V}_{0}}}{\sqrt{3}}\]                          

    B) \[{{V}_{0}}\]

    C) \[\frac{{{V}_{0}}}{\sqrt{2}}\]                          

    D) \[\frac{{{V}_{0}}}{2}\]

    Correct Answer: C

    Solution :

    (c) \[\frac{{{V}_{0}}}{\sqrt{2}}\]                         \[V={{V}_{0}}\] for \[0\le t\le \frac{T}{2}\]                         \[V=0\] for \[\frac{T}{2}\le t\le T\]             \[{{V}_{rms}}={{\left[ \frac{\int{_{0}^{T}{{V}^{2}}dt}}{\int{_{0}^{T}dt}} \right]}^{1/2}}={{\left[ \frac{\int{_{0}^{T/2}V_{0}^{2}dt+\int{_{T/2}^{T}(0)dt}}}{\int{_{0}^{T}dt}} \right]}^{1/2}}\]             \[={{\left[ \frac{V_{0}^{2}}{T}[t]_{0}^{T/2} \right]}^{1/2}}={{\left[ \frac{V_{0}^{2}}{T}\left( \frac{T}{2} \right) \right]}^{1/2}}=\frac{{{V}_{0}}}{\sqrt{2}}\]


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